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Geometry · Chapter 36

3-D Geometry

Cubes, boxes, cylinders, cones, spheres and pyramids: their volume and surface-area formulas, space diagonals and slant heights, and the big trick for 3-D problems: slice through the centers and solve a 2-D picture.

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Cube

In this section you will be able to find a cube's volume, surface area and space diagonal from its side.

A cube’s space diagonal is a right triangle on top of a right triangle: first 2 a\sqrt2,a across a face, then 3 a\sqrt3,a through the middle.

Six equal square faces give S=6a2S = 6a^2, and stacking aa layers of a×aa \times a unit cubes gives V=a3V = a^3.

Look:

The face diagonal 2 a\sqrt2,a and one edge aa are the legs of a right triangle whose hypotenuse is the space diagonal: 2a2+a2=3 a\sqrt{2a^2 + a^2} = \sqrt3,a.

Exploreplay first, formulas later

Cube (side 2): volume 8, surface area 24, face diagonal 2√2, space diagonal 2√3

side a2
turn30°
tilt30°
unfold0%

Cube: side 2. Drag the picture or use turn and tilt.

Volume 8
Surface area 24
  • face diagonal: 222\sqrt{2}
  • space diagonal: 232\sqrt{3}

Cube (side 2): volume 8, surface area 24, face diagonal 2√2, space diagonal 2√3

Name it

Theorem 36.1.1 · Volume and Surface Area of a Cube

For a cube with side length aa:

Volume=a3,Surface area=6a2,\text{Volume} = a^3, \qquad \text{Surface area} = 6a^2,

and the space diagonal (from a corner to the opposite corner, through the inside) has length

3 a.\sqrt{3}\,a.

2 × 2 × 2 box: face diagonal √(2² + 2²) = 2√2; space diagonal √(2² + 2² + 2²) = 2√3

length2
width2
height2
turn30°
2222√22√3
face 2√2
22+22=22\sqrt{2^2 + 2^2} = 2\sqrt{2}
space 2√3
22+22+22=23\sqrt{2^2 + 2^2 + 2^2} = 2\sqrt{3}

Two right triangles: legs 2,22, 2 give the face diagonal; legs 22,22\sqrt{2}, 2 give the space diagonal.

2 × 2 × 2 box: face diagonal √(2² + 2²) = 2√2; space diagonal √(2² + 2² + 2²) = 2√3

Contest cornerreal contest problems

Problem 36.10.1

AMC 10A

Seven cubes, whose volumes are 11, 88, 2727, 6464, 125125, 216216, and 343343 cubic units, are stacked vertically to form a tower in which the volumes of the cubes decrease from bottom to top. Except for the bottom cube, the bottom face of each cube lies completely on top of the cube below it. What is the total surface area of the tower (including the bottom) in square units?

Problem 36.10.35(additional)

AMC 10

A sphere is inscribed in a cube that has a surface area of 2424 square meters. A second cube is then inscribed within the sphere. What is the surface area in square meters of the inner cube?

Checkpoint for section 36.1

Get 2 of 3 right to master this section. One try each, no hints.
1

A cube has volume 6464. What is its surface area?

2

A cube has space diagonal 66. What is its side length?

3

A sphere is inscribed in a cube that has a surface area of 2424 square meters. A second cube is then inscribed within the sphere. What is the surface area in square meters of the inner cube?

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Rectangular Prism

In this section you will be able to find a box's volume, surface area and space diagonal from its three dimensions.

Volume multiplies the three dimensions; surface area adds six faces that come in three matching pairs.

A box with length ll, width bb and height hh has V=lbhV = lbh and S=2(lb+bh+lh)S = 2(lb + bh + lh).

Look:

The space diagonal uses the Pythagorean Theorem twice: l2+b2\sqrt{l^2 + b^2} across the floor, then up by hh.

Exploreplay first, formulas later

Box (length 3, width 4, height 5): volume 60, surface area 94, space diagonal 5√2

length l3
width b4
height h5
turn30°
tilt30°
unfold0%

Box: length 3, width 4, height 5. Drag the picture or use turn and tilt.

Volume 60
Surface area 94
  • space diagonal: 525\sqrt{2}

Box (length 3, width 4, height 5): volume 60, surface area 94, space diagonal 5√2

Name it

Theorem 36.2.1 · Volume and Surface Area of a Rectangular Prism

For a box with length ll, width bb and height hh:

V=lbh,S=2(lb+bh+lh),V = lbh, \qquad S = 2(lb + bh + lh),

and its space diagonal has length

l2+b2+h2.\sqrt{l^2 + b^2 + h^2}.

2 × 3 × 6 box: press Face diagonal to start

length2
width3
height6
turn30°
236
face ?
space ?

2 × 3 × 6 box: press Face diagonal to start

Try it

Problem 36.10.4

AMC 8

Isabella uses one-foot cubical blocks to build a rectangular fort that is 1212 feet long, 1010 feet wide, and 55 feet high. The floor and the four walls are all one foot thick. How many blocks does the fort contain?

Contest cornerreal contest problems

Problem 36.10.16(additional)

AMC 10

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron?

Problem 36.10.33(additional)

AMC 10

In the rectangular parallelepiped shown, AB=3AB = 3, BC=1BC = 1, and CG=2CG = 2. Point MM is the midpoint of FG‾\overline{FG}. What is the volume of the rectangular pyramid with base BCHEBCHE and apex MM?

Problem 36.10.25(additional)

AMC 10

This problem also appears in the book as 36.10.16.

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron?

Problem 36.10.40(additional)

AIME

A rectangular box has width 1212 inches, length 1616 inches, and height mn\frac{m}{n} inches, where mm and nn are relatively prime positive integers. Three faces of the box meet at a corner of the box. The center points of those three faces are the vertices of a triangle with an area of 3030 square inches. Find m+nm + n.

Checkpoint for section 36.2

Get 2 of 3 right to master this section. One try each, no hints.
1

A box measures 2×3×62 \times 3 \times 6. How long is its space diagonal?

2

A box measures 3×4×53 \times 4 \times 5. What is its surface area?

3

The centers of the faces of the right rectangular prism shown below are joined to create an octahedron. What is the volume of this octahedron?

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Cylinder

In this section you will be able to find a cylinder's volume and surface area, and unroll its side into a rectangle.

Peel the label off a soup can: it’s a rectangle 2πr2\pi r long and hh tall.

A cylinder is a stack of circles, so V=πr2hV = \pi r^2 h. Its surface is two discs plus that rectangle: S=2πr2+2πrhS = 2\pi r^2 + 2\pi r h.

Look:

On the unrolled rectangle, paths and stripes become straight lines and slanted bands. That’s how you measure anything drawn on a curved side.

Exploreplay first, formulas later

Cylinder (radius 3, height 5): volume 45π, surface area 48π, side (unrolled) 6π by 5

radius r3
height h5
turn15°
tilt30°
unfold0%

Cylinder: radius 3, height 5. Drag the picture or use turn and tilt.

Volume 45π
Surface area 48π
  • side (unrolled): 6π×56\pi \times 5

Cylinder (radius 3, height 5): volume 45π, surface area 48π, side (unrolled) 6π by 5

Name it

Theorem 36.3.1 · Volume and Surface Area of a Cylinder

For a cylinder with radius rr and height hh:

V=πr2h,S=2πr2+2πrh=2πr(r+h).V = \pi r^2 h, \qquad S = 2\pi r^2 + 2\pi r h = 2\pi r(r + h).

The two discs give 2πr22\pi r^2; the side unrolls into a rectangle 2πr2\pi r by hh.

cylinder (radius 3, height 8): side area 48π

radius r3
height h8
turn15°
tilt15°
The surface
Cut along the dashed line and flatten
Side area 48π
2πrh=48π2\pi r h = 48\pi

cylinder (radius 3, height 8): side area 48π

Try it

Problem 36.10.2

AMC 8

Jerry cuts a wedge from a 66-cm cylinder of bologna as shown by the dashed curve. Which answer choice is closest to the volume of his wedge in cubic centimeters?

Click a choice or type its letter (A–E).

Contest cornerreal contest problems

Problem 36.10.19(additional)

AMC 10A

A white cylindrical silo has a diameter of 3030 feet and a height of 8080 feet. A red stripe with a horizontal width of 33 feet is painted on the silo, as shown, making two complete revolutions around it. What is the area of the stripe in square feet?

cylinder (radius 15, height 80): side area 2400π; a stripe 3 wide making 2 turns has area 240

turn15°
tilt15°
The surface
Cut along the dashed line and flatten
Side area 2400π
Stripe area ? (hidden until the end of the example)

cylinder (radius 15, height 80): side area 2400π; a stripe 3 wide making 2 turns has area ?

Problem 36.10.32(additional)

AIME

A cylindrical log has diameter 1212 inches. A wedge is cut from the log by making two planar cuts that go entirely through the log. The first is perpendicular to the axis of the cylinder, and the plane of the second cut forms a 45∘45^\circ angle with the plane of the first cut. The intersection of these two planes has exactly one point in common with the log. The number of cubic inches in the wedge can be expressed as nπn\pi, where nn is a positive integer. Find nn.

Problem 36.10.43(additional)

AIME

A cylindrical barrel with radius 44 feet and height 1010 feet is full of water. A solid cube with side length 88 feet is set into the barrel so that the diagonal of the cube is vertical. The volume of water thus displaced is vv cubic feet. Find v2v^2.

Checkpoint for section 36.3

Get 2 of 3 right to master this section. One try each, no hints.
1

A cylinder has radius 33 and height 55. What is its total surface area? (Answer in terms of π\pi.)

2

A cylinder has volume 72π72\pi and radius 33. What is its height?

3

A white cylindrical silo has a diameter of 3030 feet and a height of 8080 feet. A red stripe with a horizontal width of 33 feet is painted on the silo, as shown, making two complete revolutions around it. What is the area of the stripe in square feet?

cylinder (radius 15, height 80): side area 2400π; a stripe 3 wide making 2 turns has area 240

turn15°
tilt15°
The surface
Cut along the dashed line and flatten
Side area 2400π
Stripe area ? (hidden until the end of the example)

cylinder (radius 15, height 80): side area 2400π; a stripe 3 wide making 2 turns has area ?

36.40%

Cone

In this section you will be able to use a cone's volume, surface area and slant height, and work with frustums.

A cone is exactly one third of the cylinder around it.

V=13πr2hV = \frac13 \pi r^2 h. The slant height s=r2+h2s = \sqrt{r^2 + h^2} is the hypotenuse of the right triangle you see from the side, and the side area is πrs\pi r s.

Look:

Cut a cone parallel to its base and the small cone on top is similar to the whole one. If its height is kk times as big, its volume is k3k^3 times as big.

Exploreplay first, formulas later

Cone (radius 3, height 4): volume 12π, surface area 24π, slant height 5, sector angle 216°

radius r3
height h4
turn15°
tilt30°
unfold0%

Cone: radius 3, height 4. Drag the picture or use turn and tilt.

Volume 12π
Surface area 24π
  • slant height: 55
  • sector angle: 216∘216^\circ

Cone (radius 3, height 4): volume 12π, surface area 24π, slant height 5, sector angle 216°

Name it

Theorem 36.4.1 · Volume and Surface Area of a Cone

For a cone with radius rr, height hh and slant height ss:

V=13πr2h,S=πr2+πrs=πr(r+s).V = \frac13 \pi r^2 h, \qquad S = \pi r^2 + \pi r s = \pi r(r + s).

In words: one third of π⋅radius2⋅height\pi \cdot \text{radius}^2 \cdot \text{height}, and the base πr2\pi r^2 plus the side π⋅radius⋅slant height\pi \cdot \text{radius} \cdot \text{slant height}.

cone 12π poured 0 times into a cylinder of 36π: empty

radius r3
height h4
cone: 12πcylinder: 36πempty
0 × 12π = 0π of 36π

cone 12π poured 0 times into a cylinder of 36π: empty

Remark 36.4.2 · Slant Height

The slant height ss is the distance from the tip of the cone to the edge of its base. The height, the radius and the slant height make a right triangle, so

s=r2+h2=radius2+height2.s = \sqrt{r^2 + h^2} = \sqrt{\text{radius}^2 + \text{height}^2}.

cone (radius 3, height 4): side area 15π; unrolled: a sector of radius 5 and angle 216°; volume 12π

radius r3
height h4
turn15°
tilt15°
The surface
Cut along the dashed line and flatten
Side area 15π
πrs=π⋅3⋅5=15π\pi r s = \pi \cdot 3 \cdot 5 = 15\pi
Volume 12π
13πr2h\tfrac13 \pi r^2 h

slant 5 · sector angle 216°

cone (radius 3, height 4): side area 15π; unrolled: a sector of radius 5 and angle 216°; volume 12π

Try it

Problem 36.10.7

AMC 10/12

An inverted cone with base radius 1212 cm and height 1818 cm is full of water. The water is poured into a tall cylinder whose horizontal base has a radius of 2424 cm. What is the height in centimeters of the water in the cylinder?

Contest cornerreal contest problems

Problem 36.10.20(additional)

AMC 10

A right circular cylinder with its diameter equal to its height is inscribed in a right circular cone. The cone has diameter 1010 and altitude 1212, and the axes of the cylinder and cone coincide. Find the radius of the cylinder.

Cone cut by a vertical plane through the axis at 0°: 0 spheres cut; the section is a triangle with base 10 and height 12

cut direction0°
turn30°
tilt15°
The solid and the cutting plane. Drag the solid to turn it.
rhs
The section, seen face on
slant height = 13

Cone cut by a vertical plane through the axis at 0°: 0 spheres cut; the section is a triangle with base 10 and height 12

Problem 36.10.26(additional)

AMC 12

An ice-cream novelty item consists of a cup in the shape of a 44-inch-tall frustum of a right circular cone, with a 22-inch-diameter base at the bottom and a 44-inch-diameter base at the top, packed solid with ice cream, together with a solid cone of ice cream of height 44 inches, whose base, at the bottom, is the top base of the frustum. What is the total volume of the ice cream, in cubic inches?

Problem 36.10.5

MATHCOUNTS

The two cones shown have parallel bases and common apex TT. TW=32TW = 32 m, WV=8WV = 8 m, and ZY=5ZY = 5 m. What is the volume of the frustum with circle WW and circle ZZ as its bases? Express your answer in terms of π\pi.

Problem 36.10.15(additional)

MATHCOUNTS

A right circular cone is sliced into four pieces by planes parallel to its base, as shown in the figure. All of these pieces have the same height. What is the ratio of the volume of the second-largest piece to the volume of the largest piece? Express your answer as a common fraction.

Small cone is 1/4 as tall: area ratio 1/16, volume ratio 1/64

slices4
cut after slice1
1/4 h
lengths1/4
areas1/16
volumes1/64

The rest of the cone (a frustum) is 1−164=63641 - \tfrac{1}{64} = \tfrac{63}{64} of the volume.

Small cone is 1/4 as tall: area ratio 1/16, volume ratio 1/64

Problem 36.10.8

AMC 10/12

Two right circular cones with vertices facing down as shown in the figure below contain the same amount of liquid. The radii of the tops of the liquid surfaces are 33 cm and 66 cm. Into each cone is dropped a spherical marble of radius 11 cm, which sinks to the bottom and is completely submerged without spilling any liquid. What is the ratio of the rise of the liquid level in the narrow cone to the rise of the liquid level in the wide cone?

Problem 36.10.29(additional)

AMC 10

Jesse cuts a circular paper disk of radius 1212 along two radii to form two sectors, the smaller having a central angle of 120120 degrees. He makes two circular cones, using each sector to form the lateral surface of a cone. What is the ratio of the volume of the smaller cone to that of the larger?

cone (radius 4, height 8√2): side area 48π; unrolled: a sector of radius 12 and angle 120°; volume ≈ 189.56

turn15°
tilt15°
The surface
Cut along the dashed line and flatten
Side area 48π
Volume ? (hidden until the end of the example)

slant 12 · sector angle 120°

cone (radius 4, height 8√2): side area 48π; unrolled: a sector of radius 12 and angle 120°; volume ?

Click a choice or type its letter (A–E).

Problem 36.10.37(additional)

AIME

When a right triangle is rotated about one leg, the volume of the cone produced is 800π800\pi cm3^3. When the triangle is rotated about the other leg, the volume of the cone produced is 1920π1920\pi cm3^3. What is the length (in cm) of the hypotenuse of the triangle?

Problem 36.10.39(additional)

AIME

A container in the shape of a right circular cone is 1212 inches tall and its base has a 55-inch radius. The liquid that is sealed inside is 99 inches deep when the cone is held with its point down and its base horizontal. When the liquid is held with its point up and its base horizontal, the height of the liquid is m−np3m - n\sqrt[3]{p}, from the base where mm, nn, and pp are positive integers and pp is not divisible by the cube of any prime number. Find m+n+pm + n + p.

Problem 36.10.13

AMC 12

A lampshade is made in the form of the lateral surface of the frustum of a right circular cone. The height of the frustum is 333\sqrt3 inches, its top diameter is 66 inches, and its bottom diameter is 1212 inches. A bug is at the bottom of the lampshade and there is a glob of honey on the top edge of the lampshade at the spot farthest from the bug. The bug wants to crawl to the honey, but it must stay on the surface of the lampshade. What is the length in inches of its shortest path to the honey?

frustum (radii 6 and 3, height 3√3): side area 54π; unrolled: a sector of radius 6 and angle 180°

turn15°
tilt15°
BugHoney
The surface
BugHoney
Cut along the dashed line and flatten
Side area 54π

slant 6 · sector angle 180°

frustum (radii 6 and 3, height 3√3): side area 54π; unrolled: a sector of radius 6 and angle 180°

Checkpoint for section 36.4

Get 2 of 3 right to master this section. One try each, no hints.
1

A cone has radius 66 and height 88. What is its slant height?

2

A cone has radius 33 and height 44. What is its total surface area? (Answer in terms of π\pi.)

3

An ice-cream novelty item consists of a cup in the shape of a 44-inch-tall frustum of a right circular cone, with a 22-inch-diameter base at the bottom and a 44-inch-diameter base at the top, packed solid with ice cream, together with a solid cone of ice cream of height 44 inches, whose base, at the bottom, is the top base of the frustum. What is the total volume of the ice cream, in cubic inches?

36.50%

Sphere

In this section you will be able to use a sphere's volume and surface area, and see how they grow with the radius.

A sphere’s surface is exactly four of its great circles: 4πr24\pi r^2.

V=43πr3V = \frac43 \pi r^3 and S=4πr2S = 4\pi r^2. Volume grows like r3r^3 and area like r2r^2, the same rule as for any similar solids.

Exploreplay first, formulas later

Sphere (radius 3): volume 36π, surface area 36π

radius r3
turn30°
tilt30°

Sphere: radius 3. Drag the picture or use turn and tilt.

Volume 36π
Surface area 36π

Sphere (radius 3): volume 36π, surface area 36π

Name it

Theorem 36.5.1 · Volume and Surface Area of a Sphere

For a sphere with radius rr:

V=43πr3,S=4πr2.V = \frac43 \pi r^3, \qquad S = 4\pi r^2.

Try it

Problem 36.10.22(additional)

AMC 10

An ice cream cone consists of a sphere of vanilla ice cream and a right circular cone that has the same diameter as the sphere. If the ice cream melts, it will exactly fill the cone. Assume that the melted ice cream occupies 75%75\% of the volume of the frozen ice cream. What is the ratio of the cone's height to its radius? (Note: a cone with radius rr and height hh has volume πr2h/3\pi r^2 h/3 and a sphere with radius rr has volume 4πr3/34\pi r^3/3.)

Problem 36.10.36(additional)

AMC 10

Logan is constructing a scaled model of his town. The city's water tower stands 4040 meters high, and the top portion is a sphere that holds 100,000100{,}000 liters of water. Logan's miniature water tower holds 0.10.1 liters. How tall, in meters, should Logan make his tower?

Contest cornerreal contest problems

Problem 36.10.6

AMC 10

Four congruent semicircles are drawn on the surface of a sphere with radius 22, as shown, creating a closed curve that divides the surface into two congruent regions. The length of the curve is πn\pi\sqrt{n}. What is nn?

Checkpoint for section 36.5

Get 2 of 3 right to master this section. One try each, no hints.
1

A sphere has surface area 36π36\pi. What is its volume? (Answer in terms of π\pi.)

2

If the radius of a sphere is doubled, by what factor does its volume grow?

3

An ice cream cone consists of a sphere of vanilla ice cream and a right circular cone that has the same diameter as the sphere. If the ice cream melts, it will exactly fill the cone. Assume that the melted ice cream occupies 75%75\% of the volume of the frozen ice cream. What is the ratio of the cone's height to its radius? (Note: a cone with radius rr and height hh has volume πr2h/3\pi r^2 h/3 and a sphere with radius rr has volume 4πr3/34\pi r^3/3.)

36.60%

Tetrahedron

In this section you will be able to find the volume of any tetrahedron, and of a regular one from its edge.

Any tetrahedron is 13⋅base⋅height\frac13 \cdot \text{base} \cdot \text{height}; a regular one is 212s3\frac{\sqrt2}{12}s^3.

Pick the most convenient face as the base. When three edges meet at right angles (like a box corner), use the right triangle as the base and the third edge as the height: V=16abcV = \frac16 abc.

Exploreplay first, formulas later

Tetrahedron (edge 6): volume 18√2, surface area 36√3, height 4.9

edge s6
turn30°
tilt30°
unfold0%

Tetrahedron: edge 6. Drag the picture or use turn and tilt.

Volume 18√2
V=212s3=182V = \tfrac{\sqrt2}{12}s^3 = 18\sqrt{2}
Surface area 36√3
S=4⋅34s2=363S = 4 \cdot \tfrac{\sqrt3}{4}s^2 = 36\sqrt{3}
  • height: 4.94.9

Tetrahedron (edge 6): volume 18√2, surface area 36√3, height 4.9

Name it

Theorem 36.6.1 · Volume of a Tetrahedron

For any tetrahedron:

V=13⋅base area⋅height,V = \frac13 \cdot \text{base area} \cdot \text{height},

where the height is the distance from the fourth vertex to the plane of the base.

Theorem 36.6.2 · Volume of a Regular Tetrahedron

A regular tetrahedron (all six edges equal to ss) has volume

V=212s3.V = \frac{\sqrt2}{12} s^3.

Contest cornerreal contest problems

Problem 36.10.10

AMC 10

What is the volume of tetrahedron ABCDABCD with edge lengths AB=2AB = 2, AC=3AC = 3, AD=4AD = 4, BC=13BC = \sqrt{13}, BD=25BD = 2\sqrt5, and CD=5CD = 5?

Problem 36.10.23(additional)

AMC 12

Triangle ABCABC, with sides of length 55, 66, and 77, has one vertex on the positive xx-axis, one on the positive yy-axis, and one on the positive zz-axis. Let OO be the origin. What is the volume of tetrahedron OABCOABC?

Problem 36.10.42(additional)

AIME

In a regular tetrahedron the centers of the four faces are the vertices of a smaller tetrahedron. The ratio of the volume of the smaller tetrahedron to that of the larger is m/nm/n, where mm and nn are relatively prime positive integers. Find m+nm + n.

Problem 36.10.14

AIMEChallenge

Let ABCDABCD be a tetrahedron such that AB=CD=41AB = CD = \sqrt{41}, AC=BD=80AC = BD = \sqrt{80}, and BC=AD=89BC = AD = \sqrt{89}. There exists a point II inside the tetrahedron such that the distances from II to each of the faces of the tetrahedron are all equal. This distance can be written in the form mnp\frac{m\sqrt n}{p}, where mm, nn, and pp are positive integers, mm and pp are relatively prime, and nn is not divisible by the square of any prime. Find m+n+pm + n + p.

Checkpoint for section 36.6

Get 2 of 3 right to master this section. One try each, no hints.
1

A regular tetrahedron has edge 66. What is its volume?

2

A tetrahedron has a base of area 1515 and height 44. What is its volume?

3

Triangle ABCABC, with sides of length 55, 66, and 77, has one vertex on the positive xx-axis, one on the positive yy-axis, and one on the positive zz-axis. Let OO be the origin. What is the volume of tetrahedron OABCOABC?

36.70%

Pyramid

In this section you will be able to find the volume of a pyramid, and use similar pyramids cut parallel to the base.

Pyramids are one third of prisms. With a square base and all edges equal, V=26s3V = \frac{\sqrt2}{6}s^3.

A plane parallel to the base cuts off a small pyramid similar to the whole one. With scale factor kk, lengths scale by kk, areas by k2k^2 and volumes by k3k^3.

Exploreplay first, formulas later

Square pyramid (base side 6, height 4.24): volume 36√2, surface area 98.35, face height 3√3, height 3√2

base a6
height h4.24
turn30°
tilt30°
unfold0%

Square pyramid: base side 6, height 4.24. Drag the picture or use turn and tilt.

Volume 36√2
V=26s3=362V = \tfrac{\sqrt2}{6}s^3 = 36\sqrt{2}
Surface area 98.35
S=s2+4⋅34s2=98.35S = s^2 + 4 \cdot \tfrac{\sqrt3}{4}s^2 = 98.35
  • face height: 333\sqrt{3}
  • height: 323\sqrt{2}

Square pyramid (base side 6, height 4.24): volume 36√2, surface area 98.35, face height 3√3, height 3√2

Name it

Theorem 36.7.1 · Volume of a Pyramid

For any pyramid:

V=13⋅base area⋅height.V = \frac13 \cdot \text{base area} \cdot \text{height}.

A pyramid fills exactly one third of the prism with the same base and height.

pyramid 32 poured 0 times into a prism of 96: empty

base side a4
height h6
pyramid: 32prism: 96empty
0 × 32 = 0 of 96

pyramid 32 poured 0 times into a prism of 96: empty

Theorem 36.7.2 · Volume of a Regular Square Pyramid

When the pyramid has a square base and all eight edges are equal to ss:

V=26s3.V = \frac{\sqrt2}{6} s^3.

Contest cornerreal contest problems

Problem 36.10.18(additional)

AMC 10

A pyramid with a square base is cut by a plane that is parallel to its base and 22 units from the base. The surface area of the smaller pyramid that is cut from the top is half the surface area of the original pyramid. What is the altitude of the original pyramid?

Problem 36.10.27(additional)

AMC 12

A pyramid has a square base with side of length 11 and has lateral faces that are equilateral triangles. A cube is placed within the pyramid so that one face is on the base of the pyramid and its opposite face has all its edges on the lateral faces of the pyramid. What is the volume of this cube?

Problem 36.10.28(additional)

AMC 10

This problem also appears in the book as 36.10.27.

A pyramid has a square base with sides of length 11 and has lateral faces that are equilateral triangles. A cube is placed within the pyramid so that one face is on the base of the pyramid and its opposite face has all its edges on the lateral faces of the pyramid. What is the volume of this cube?

Problem 36.10.17(additional)

AMC 12B

A container has a 1×11 \times 1 square bottom, a 3×33 \times 3 open square top, and four congruent trapezoidal sides, as shown. Starting when the container is empty, a hose that runs water at a constant rate takes 3535 minutes to fill the container up to the midline of the trapezoids. How many more minutes will it take to fill the remainder of the container?

Problem 36.10.11

AMC 12

Let ABCDABCD be a rectangle and let DM‾\overline{DM} be a segment perpendicular to the plane of ABCDABCD. Suppose that DM‾\overline{DM} has integer length, and the lengths of MA‾\overline{MA}, MC‾\overline{MC}, and MB‾\overline{MB} are consecutive odd positive integers (in this order). What is the volume of pyramid MABCDMABCD?

Checkpoint for section 36.7

Get 2 of 3 right to master this section. One try each, no hints.
1

A pyramid has a 6×66 \times 6 square base and height 44. What is its volume?

2

A pyramid is cut by a plane parallel to its base, halfway up. What fraction of the pyramid's volume is the small pyramid on top?

3

A container has a 1×11 \times 1 square bottom, a 3×33 \times 3 open square top, and four congruent trapezoidal sides, as shown. Starting when the container is empty, a hose that runs water at a constant rate takes 3535 minutes to fill the container up to the midline of the trapezoids. How many more minutes will it take to fill the remainder of the container?

36.80%

Volume of Complex Polyhedrons

In this section you will be able to find the volume of a solid built from pieces you know: pyramids, prisms and cut-off corners.

Fold six triangles up around a hexagon. Where does the apex land?

Most “strange” solids are a pyramid, a prism, or a box with pieces added or cut away. Find the height with a right triangle, then use 13⋅base⋅height\frac13 \cdot \text{base} \cdot \text{height} on each piece.

Exploreplay first, formulas later

Hexagonal pyramid (base side 4, slanted edge 5): volume 24√3, surface area 96.56, height 3, base area 24√3. Unfolded into its net

base side a4
slanted edge b5
turn30°
tilt60°
unfold100%

Hexagonal pyramid: base side 4, slanted edge 5. Drag the picture or use turn and tilt.

Volume 24√3
Surface area 96.56
  • height: 33
  • base area: 24324\sqrt{3}

Hexagonal pyramid (base side 4, slanted edge 5): volume 24√3, surface area 96.56, height 3, base area 24√3. Unfolded into its net

Watch itpredict, then reveal

Example 36.1

AMC 10

A regular hexagon with sides of length 66 has an isosceles triangle attached to each side. Each of these triangles has two sides of length 88. The isosceles triangles are folded to make a pyramid with the hexagon as the base of the pyramid. What is the volume of the pyramid?

Solid viewer (its total is revealed at the end of the example)

turn30°
tilt60°
unfold100%

Hexagonal pyramid: base side 6, slanted edge 8. Drag the picture or use turn and tilt.

Volume ? (hidden until the end of the example)
Surface area 227.02

Hexagonal pyramid (base side 6, slanted edge 8): volume ?, surface area 227.02. Unfolded into its net

  1. 1

    Fold the six triangles up until their tips meet. Where is the apex, compared with the hexagon?

open on YouTube

Contest cornerreal contest problems

Problem 36.10.21(additional)

AMC 12

This problem also appears in the book as 36.1.

A regular hexagon with sides of length 66 has an isosceles triangle attached to each side. Each of these triangles has two sides of length 88. The isosceles triangles are folded to make a pyramid with the hexagon as the base of the pyramid. What is the volume of the pyramid?

Problem 36.10.9

AMC 10A

A bowl is formed by attaching four regular hexagons of side 11 to a square of side 11. The edges of adjacent hexagons coincide, as shown in the figure. What is the area of the octagon obtained by joining the top eight vertices of the four hexagons, situated on the rim of the bowl?

Click a choice or type its letter (A–E).

Problem 36.10.12

AMC 12A

The base of the pentahedron shown below is a 13×813 \times 8 rectangle, and its lateral faces are two isosceles triangles with base of length 88 and congruent sides of length 1313, and two isosceles trapezoids with bases of length 77 and 1313 and nonparallel sides of length 1313. What is the volume of the pentahedron?

Problem 36.10.38(additional)

AIME

The solid shown has a square base of side length ss. The upper edge is parallel to the base and has length 2s2s. All other edges have length ss. Given that s=62s = 6\sqrt2, what is the volume of the solid?

Checkpoint for section 36.8

Get 2 of 3 right to master this section. One try each, no hints.
1

A regular hexagon has side 33. What is its area?

2

A pyramid on a regular hexagon of side 33 has slanted edges of length 55. What is its height?

3

What is the volume of that pyramid (hexagon side 33, slanted edges 55)?

36.90%

Cross Sections

In this section you will be able to slice a 3-D figure through its centers and solve the 2-D picture you get.

3-D problems become 2-D when you slice through the centers.

Spheres touching each other or a flat face: slice through their centers, and each sphere becomes a circle of the same radius. Touching spheres have centers r1+r2r_1 + r_2 apart.

Look:

A sphere cut by a plane at distance dd from its center gives a circle of radius R2−d2\sqrt{R^2 - d^2}. That one right triangle solves most “sphere and plane” problems.

Exploreplay first, formulas later

Cube of side 1 cut by the plane through mid BC, mid DH, mid EF: the section is a regular hexagon of area 3√3/4; the pieces have volumes 1/2 and 1/2

point 1mid BC
point 2mid DH
point 3mid EF
turn30°
tilt15°
ABCDEFGH
The solid and the cutting plane. Drag the solid to turn it.
The section, seen face on
section: regular hexagon area 3√3/4
pieces: 1/2 + 1/2

Cube of side 1 cut by the plane through mid BC, mid DH, mid EF: the section is a regular hexagon of area 3√3/4; the pieces have volumes 1/2 and 1/2

Watch itpredict, then reveal

Example 36.2

AIME

Eight spheres of radius 100100 are placed on a flat surface so that each sphere is tangent to two others and their centers are the vertices of a regular octagon. A ninth sphere is placed on the flat surface so that it is tangent to each of the other eight spheres. The radius of this last sphere is a+bca + b\sqrt{c}, where aa, bb, and cc are positive integers, and cc is not divisible by the square of any prime. Find a+b+ca + b + c.

Geometry figure (its total is revealed at the end of the example)

Figure: circle centered at C0; circle centered at C1; circle centered at C2; circle centered at C3; circle centered at C4; circle centered at C5; circle centered at C6; circle centered at C7; 8-gon C0C1C2C3C4C5C6C7; C0C1 = 200.

  1. 1

    Look down from above. Where are the eight centers, and how far apart are neighbors?

    Predict first:
open on YouTube

Example 36.3

AIME

A right prism with height hh has bases that are regular hexagons with sides of length 1212. A vertex AA of the prism and its three adjacent vertices are the vertices of a triangular pyramid. The dihedral angle (the angle between the two planes) formed by the face of the pyramid that lies in a base of the prism and the face of the pyramid that does not contain AA measures 6060 degrees. Find h2h^2.

  1. 1

    AA's three neighbors are BB and FF in the base and A′A' straight above AA. Which face of the pyramid lies in the base, and which one doesn't contain AA?

open on YouTube

Example 36.4

AMC 10

A sphere with center OO has radius 66. A triangle with sides of length 1515, 1515, and 2424 is situated in space so that each of its sides is tangent to the sphere. What is the distance between OO and the plane determined by the triangle?

Cross-section (its total is revealed at the end of the example)

cut direction90°
turn15°
tilt30°
O
The solid and the cutting plane. Drag the solid to turn it.
The section, seen face on

Sphere and triangle cut by a vertical plane through the axis at 90°: 1 sphere cut; O is ? from the triangle's plane

  1. 1

    Each side touches the sphere at one point. What does the triangle's plane cut out of the sphere, and how is it related to the triangle?

open on YouTube

Example 36.5

AMC 10

Inside a right circular cone with base radius 55 and height 1212 are three congruent spheres with radius rr. Each sphere is tangent to the other two spheres and also tangent to the base and side of the cone. What is rr?

Cross-section (its total is revealed at the end of the example)

cut direction0°
turn15°
tilt15°
The solid and the cutting plane. Drag the solid to turn it.
The section, seen face on
sphere radius r = ? (hidden until the end of the example)

Cone with three spheres cut by a vertical plane through the axis at 0°: 1 sphere cut; each sphere has radius ?

  1. 1

    Look from above. The three centers sit at height rr. What shape do they form, and what is its side?

    Predict first:
    Click a choice or type its letter (A–E).
open on YouTube

Example 36.6

AMC 12

A 4×4×h4 \times 4 \times h rectangular box contains a sphere of radius 22 and eight smaller spheres of radius 11. The smaller spheres are each tangent to three sides of the box, and the larger sphere is tangent to each of the smaller spheres. What is hh?

Cross-section (its total is revealed at the end of the example)

cut direction45°
turn15°
tilt15°
O
The solid and the cutting plane. Drag the solid to turn it.
The section, seen face on
box height h = ? (hidden until the end of the example)

Box of spheres cut by a vertical plane through the axis at 45°: 5 spheres cut; the box height is ?

  1. 1

    Put a corner of the box at the origin. Where is the center of the small sphere in that corner?

open on YouTube

Contest cornerreal contest problems

Problem 36.10.3

AMC 8

In the cube ABCDEFGHABCDEFGH with opposite vertices CC and EE, JJ and II are the midpoints of segments FB‾\overline{FB} and HD‾\overline{HD}, respectively. Let RR be the ratio of the area of the cross-section EJCIEJCI to the area of one of the faces of the cube. What is R2R^2?

Cube of side 1 cut by the plane through E, J, C: the section is a rhombus of area √6/2; the pieces have volumes 1/2 and 1/2

turn30°
tilt15°
ABCDEFGHJI
The solid and the cutting plane. Drag the solid to turn it.
JCIE
The section, seen face on
section: rhombus area ? (hidden until the end of the example)
pieces: ? (hidden until the end of the example)

Cube of side 1 cut by the plane through E, J, C: the section is a rhombus of area ?; the pieces have volumes ? and ?

Problem 36.10.24(additional)

AMC 10

A cube with side length 11 is sliced by a plane that passes through two diagonally opposite vertices AA and CC and the midpoints BB and DD of two opposite edges not containing AA or CC, as shown. What is the area of quadrilateral ABCDABCD?

Problem 36.10.41(additional)

AMC 10

Three mutually tangent spheres of radius 11 rest on a horizontal plane. A sphere of radius 22 rests on them. What is the distance from the plane to the top of the larger sphere?

Problem 36.10.30(additional)

AMC 10/12

Six spheres of radius 11 are positioned so that their centers are at the vertices of a regular hexagon of side length 22. The six spheres are internally tangent to a larger sphere whose center is the center of the hexagon. An eighth sphere is externally tangent to the six smaller spheres and internally tangent to the larger sphere. What is the radius of this eighth sphere?

Problem 36.10.31(additional)

AMC 10

A sphere is inscribed in a truncated right circular cone as shown. The volume of the truncated cone is twice that of the sphere. What is the ratio of the radius of the bottom base of the truncated cone to the radius of the top base of the truncated cone?

Problem 36.10.44(additional)

AIMEChallenge

Cube ABCDEFGHABCDEFGH, labeled as shown below, has edge length 11 and is cut by a plane passing through vertex DD and the midpoints MM and NN of AB‾\overline{AB} and CG‾\overline{CG} respectively. The plane divides the cube into two solids. The volume of the larger of the two solids can be written in the form pq\frac{p}{q}, where pp and qq are relatively prime positive integers. Find p+qp + q.

Cube of side 1 cut by the plane through D, M, N: the section is a trapezoid of area ≈ 0.859; the pieces have volumes 7/48 and 41/48

turn30°
tilt15°
ABCDEFGHMN
The solid and the cutting plane. Drag the solid to turn it.
DMN
The section, seen face on
section: trapezoid area ? (hidden until the end of the example)
pieces: ? (hidden until the end of the example)

Cube of side 1 cut by the plane through D, M, N: the section is a trapezoid of area ?; the pieces have volumes ? and ?

Checkpoint for section 36.9

Get 2 of 3 right to master this section. One try each, no hints.
1

A plane cuts a unit cube through the vertices BB, DD and EE (three corners next to AA). What is the area of the triangle cut out?

2

A cone has base radius 33 and height 44. A sphere sits inside, touching the base and the side all the way round. Slicing through the axis, what is the sphere's radius? (It is the inradius of the 66-55-55 triangle.)

3

Centers of adjacent faces of a unit cube are joined to form a regular octahedron. What is the volume of this octahedron?

36.10

Practice Problems

In this section you will be able to mix the chapter's tools on one more contest problem.

Mixed practice: pick the formula, find the hidden right triangle, or slice the solid.

Most practice problems for this chapter appear in the lesson they use. This last one mixes two ideas: face centers and the 13\frac13 rule.

Contest cornerreal contest problems

Problem 36.10.34(additional)

AMC 10

Centers of adjacent faces of a unit cube are joined to form a regular octahedron. What is the volume of this octahedron?