Skip to content
Geometry · Chapter 33

Quadrilaterals

Squares, rectangles, rhombi, parallelograms and trapezoids: their area formulas, what their diagonals do, and how to cut any quadrilateral into triangles you can handle.

You'll need
open on YouTube
33.10%

Square

In this section you will be able to find the area of a square, and of a square tilted inside another square.

A square is the most symmetric quadrilateral. Tilt one inside another square, and the leftover corners are four matching right triangles.

A square with side ss has area s2s^2 and perimeter 4s4s. A square with diagonal dd has area d22\frac{d^2}{2}.

Look:

When a square EFGHEFGH has a corner on each side of square ABCDABCD, its side is the hypotenuse of a corner triangle with legs AEAE and EBEB. So [EFGH]=AE2+EB2[EFGH] = AE^2 + EB^2.

Exploreplay first, formulas later

Square EFGH inside square ABCD with AE = 6, EB = 2: [EFGH]/[ABCD] = 5/8

EB2
ABCD2√102√102√102√10EFGH
Square
  • All 4 sides equal: yes
  • 4 right angles: yes
  • Both pairs of opposite sides parallel: yes
  • At least one pair of opposite sides parallel: yes
  • Diagonals are equal: yes
  • Diagonals are perpendicular: yes
  • Diagonals cut each other in half: yes
[EFGH] : [ABCD] = 40 : 64 = 5/8

AE = 6, EB = 2. Square EFGH has area 6² + 2² = 40; ABCD has area 64. Ratio 5/8.

Name it

Theorem 33.1.1 · Area of a Square

Any square with side length ss has an area of

s2s^2

and a perimeter of

4s.4s.

Try it

Problem 33.6.3

AMC 10

Square EFGHEFGH has one vertex on each side of square ABCDABCD. Point EE is on ABAB with AE=7⋅EBAE = 7 \cdot EB. What is the ratio of the area of EFGHEFGH to the area of ABCDABCD?

Problem 33.6.12(additional)

AMC 10/12

Four congruent rectangles are placed as shown. The area of the outer square is 44 times that of the inner square. What is the ratio of the length of the longer side of each rectangle to the length of its shorter side?

Contest cornerreal contest problems

Problem 33.6.2

AMC 10

The five small shaded squares inside this unit square are congruent and have disjoint interiors. The midpoint of each side of the middle square coincides with one of the vertices of the other four small squares as shown. The common side length is a−2b\frac{a - \sqrt{2}}{b}, where aa and bb are positive integers. What is a+ba + b?

Problem 33.6.6

AMC 12

Let ABCDABCD be a square. Let E,F,GE, F, G and HH be the centers, respectively, of equilateral triangles with bases AB‾,BC‾,CD‾,\overline{AB}, \overline{BC}, \overline{CD}, and DA‾\overline{DA}, each exterior to the square. What is the ratio of the area of square EFGHEFGH to the area of square ABCDABCD?

Problem 33.6.13(additional)

AMC 10

In square ABCDABCD, points EE and HH lie on AB‾\overline{AB} and DA‾\overline{DA}, respectively, so that AE=AHAE = AH. Points FF and GG lie on BC‾\overline{BC} and CD‾\overline{CD}, respectively, and points II and JJ lie on EH‾\overline{EH} so that FI‾⊥EH‾\overline{FI} \perp \overline{EH} and GJ‾⊥EH‾\overline{GJ} \perp \overline{EH}. See the figure below. Triangle AEHAEH, quadrilateral BFIEBFIE, quadrilateral DHJGDHJG, and pentagon FCGJIFCGJI each has area 11. What is FI2FI^2?

Problem 33.6.14(additional)

AMC 10

A closed box with a square base is to be wrapped with a square sheet of wrapping paper. The box is centered on the wrapping paper with the vertices of the base lying on the midlines of the square sheet of paper, as shown in the figure. The four corners of the wrapping paper are to be folded up over the sides and brought together to meet at the center of the top of the box, point AA (seen from above, as in the figure, AA is the center of the sheet). The box has base length ww and height hh. What is the area of the sheet of wrapping paper?

Checkpoint for section 33.1

Get 2 of 3 right to master this section. One try each, no hints.
1

A square has perimeter 3636. What is its area?

2

A square has a diagonal of length 1010. What is its area?

3

Square EFGHEFGH has one vertex on each side of square ABCDABCD, which has side 55. If AE=4AE = 4 and EB=1EB = 1, what is the area of EFGHEFGH?

33.20%

Rectangle

In this section you will be able to use a rectangle's area and its diagonals, which always make two right triangles.

Rectangles are where right triangles live: every diagonal cuts one into two of them.

A rectangle with base bb and height hh has area bhbh, perimeter 2b+2h2b + 2h, and diagonals of length b2+h2\sqrt{b^2 + h^2}.

Look:

Lines parallel to the sides cut a rectangle into smaller rectangles. Name the pieces with two letters, like xx and yy, and the areas become x2x^2, xyxy and y2y^2.

Exploreplay first, formulas later

Rectangle: area 32, perimeter 24

8484ABCD
Rectangle
  • All 4 sides equal: no
  • 4 right angles: yes
  • Both pairs of opposite sides parallel: yes
  • At least one pair of opposite sides parallel: yes
  • Diagonals are equal: yes
  • Diagonals are perpendicular: no
  • Diagonals cut each other in half: yes
Rectangle: area 32, perimeter 24

Rectangle. Area 32, perimeter 24. 4 right angles; Both pairs of opposite sides parallel; At least one pair of opposite sides parallel; Diagonals are equal; Diagonals cut each other in half.

Name it

Theorem 33.2.1 · Area of a Rectangle

Any rectangle with base bb and height hh has an area of

bhbh

and a perimeter of

2b+2h.2b + 2h.

Watch itpredict, then reveal

Example 33.1

AIME

Let ABCDABCD be a square, and let EE and FF be points on AB‾\overline{AB} and BC‾\overline{BC}, respectively. The line through EE parallel to BC‾\overline{BC} and the line through FF parallel to AB‾\overline{AB} divide ABCDABCD into two squares and two nonsquare rectangles. The sum of the areas of the two squares is 910\frac{9}{10} of the area of square ABCDABCD. Find AEEB+EBAE\frac{AE}{EB} + \frac{EB}{AE}.

Geometry figure (its total is revealed at the end of the example)

Figure: quadrilateral ABCD; segment EQ; segment RF; AE = x; EB = y.

  1. 1

    Call AE=xAE = x and EB=yEB = y. What is the side of square ABCDABCD?

open on YouTube

Try it

Problem 33.6.4

AMC 10

This problem also appears in the book as 32.2.24.

Rectangle ABCDABCD has AB=3AB = 3 and BC=4BC = 4. Point EE is the foot of the perpendicular from BB to diagonal AC‾\overline{AC}. What is the area of △AED\triangle AED?

Problem 33.6.26(additional)

AMC 10

A rectangular floor measures aa by bb feet, where aa and bb are positive integers and b>ab > a. An artist paints a rectangle on the floor with the sides of the rectangle parallel to the floor. The unpainted part of the floor forms a border of width 11 foot around the painted rectangle and occupies half the area of the whole floor. How many possibilities are there for the ordered pair (a,b)(a, b)?

Contest cornerreal contest problems

Problem 33.6.21(additional)

AMC 10

In rectangle ABCDABCD, DC=2⋅CBDC = 2 \cdot CB and points EE and FF lie on AB‾\overline{AB} so that ED‾\overline{ED} and FD‾\overline{FD} trisect ∠ADC\angle ADC as shown. What is the ratio of the area of △DEF\triangle DEF to the area of rectangle ABCDABCD?

Problem 33.6.23(additional)

AMC 10

In rectangle ABCDABCD, AB=6AB = 6, AD=30AD = 30, and GG is the midpoint of AD‾\overline{AD}. Segment ABAB is extended 22 units beyond BB to point EE, and FF is the intersection of ED‾\overline{ED} and BC‾\overline{BC}. What is the area of quadrilateral BFDGBFDG?

Problem 33.6.30(additional)

AMC 12

In the figure, ABCDABCD is a square of side length 11. The rectangles JKHGJKHG and EBCFEBCF are congruent. What is BEBE?

Checkpoint for section 33.2

Get 2 of 3 right to master this section. One try each, no hints.
1

A rectangle has area 4848 and one side 66. What is its perimeter?

2

How long is a diagonal of a 5×125 \times 12 rectangle?

3

A rectangular floor measures aa by bb feet, where aa and bb are positive integers and b>ab > a. An artist paints a rectangle on the floor with the sides of the rectangle parallel to the floor. The unpainted part of the floor forms a border of width 11 foot around the painted rectangle and occupies half the area of the whole floor. How many possibilities are there for the ordered pair (a,b)(a, b)?

33.30%

Rhombus

In this section you will be able to find a rhombus's area and perimeter from its diagonals.

A rhombus is a pushed-over square: the sides stay the same, the diagonals change, and they stay perpendicular.

The diagonals of a rhombus cut it into four congruent right triangles, with legs d12\frac{d_1}{2} and d22\frac{d_2}{2}. That one picture gives both formulas.

Exploreplay first, formulas later

Rhombus: area 24, perimeter 20

5555d₁ = 8d₂ = 6ABCD
Rhombus

d₁ = 8, d₂ = 6, angle between them θ = 90°

  • All 4 sides equal: yes
  • 4 right angles: no
  • Both pairs of opposite sides parallel: yes
  • At least one pair of opposite sides parallel: yes
  • Diagonals are equal: no
  • Diagonals are perpendicular: yes
  • Diagonals cut each other in half: yes
Rhombus: area 24, perimeter 20
12d1d2=12×8×6=24,2d12+d22=264+36=20\tfrac12 d_1 d_2 = \tfrac12 \times 8 \times 6 = 24,\quad 2\sqrt{d_1^2 + d_2^2} = 2\sqrt{64 + 36} = 20

Rhombus. Area 24, perimeter 20. All 4 sides equal; Both pairs of opposite sides parallel; At least one pair of opposite sides parallel; Diagonals are perpendicular; Diagonals cut each other in half.

Name it

Theorem 33.3.1 · Area of a Rhombus

A rhombus with diagonals d1d_1 and d2d_2 has an area of

12d1d2\frac{1}{2}d_1 d_2

and a perimeter of

2d12+d22.2\sqrt{d_1^2 + d_2^2}.

Concept 33.3.2 · Rhombus

  1. All sides equal
  2. Opposite angles congruent
  3. Diagonals are perpendicular bisectors

Contest cornerreal contest problems

Problem 33.6.20(additional)

AMC 10

In rectangle PQRSPQRS, PQ=8PQ = 8 and QR=6QR = 6. Points AA and BB lie on PQ‾\overline{PQ}, points CC and DD lie on QR‾\overline{QR}, points EE and FF lie on RS‾\overline{RS}, and points GG and HH lie on SP‾\overline{SP} so that AP=BQ<4AP = BQ < 4 and the convex octagon ABCDEFGHABCDEFGH is equilateral. The length of a side of this octagon can be expressed in the form k+mnk + m\sqrt{n}, where kk, mm, and nn are integers and nn is not divisible by the square of any prime. What is k+m+nk + m + n?

Checkpoint for section 33.3

Get 2 of 3 right to master this section. One try each, no hints.
1

A rhombus has diagonals 66 and 88. What is its area?

2

A rhombus has diagonals 66 and 88. What is its perimeter?

3

A rhombus has side 1010 and one diagonal 1212. How long is the other diagonal?

33.40%

Parallelogram

In this section you will be able to find a parallelogram's area from a base and height, or from its diagonals and the angle between them.

A parallelogram has the same area as the rectangle you get by sliding a triangle from one end to the other.

Slide the top side along its own line and the height stays the same, so the area stays bhbh.

Look:

Parallel lines make parallelograms everywhere. Opposite sides of a parallelogram are equal, so a length on one side can be moved to the other.

Exploreplay first, formulas later

Parallelogram: area 30, perimeter ≈22.77

6√296√29h = 5ABCD
Parallelogram
  • All 4 sides equal: no
  • 4 right angles: no
  • Both pairs of opposite sides parallel: yes
  • At least one pair of opposite sides parallel: yes
  • Diagonals are equal: no
  • Diagonals are perpendicular: no
  • Diagonals cut each other in half: yes
Parallelogram: area 30, perimeter ≈22.77
bh=6×5=30,12d1d2sin⁡θ=12×89×41×sin⁡96.65∘=30bh = 6 \times 5 = 30,\quad \tfrac12 d_1 d_2 \sin\theta = \tfrac12 \times \sqrt{89} \times \sqrt{41} \times \sin 96.65^\circ = 30

Parallelogram. Area 30, perimeter ≈22.77. Both pairs of opposite sides parallel; At least one pair of opposite sides parallel; Diagonals cut each other in half.

Name it

Theorem 33.4.1 · Area of a Parallelogram

A parallelogram with base bb and height hh has an area of

bh.bh.

A parallelogram with diagonals d1d_1 and d2d_2 has an area of

12d1d2sin⁡θ,\frac{1}{2}d_1 d_2 \sin\theta,

where θ\theta is the angle between the diagonals (the book calls it the central angle of the parallelogram).

Concept 33.4.2 · Parallelogram Properties

  1. Diagonals bisect each other
  2. Opposite sides congruent
  3. Opposite angles congruent
  4. Base angles supplementary

Watch itpredict, then reveal

Example 33.2

AIME

In △ABC\triangle ABC, AB=425AB = 425, BC=450BC = 450, and AC=510AC = 510. An interior point PP is then drawn, and segments are drawn through PP parallel to the sides of the triangle. If these three segments are of an equal length dd, find dd.

Parallel slice (its total is revealed at the end of the example)

D′FDE′F′E450510425ABCP
segments through P
D′F = ? (hidden until the end of the example) · DE′ = ? (hidden until the end of the example) · F′E = ? (hidden until the end of the example)

Three segments through P parallel to the sides, of lengths ?, ?, ?

  1. 1

    Look at the corner CC. Which shape do CC, E′E', PP, FF make, and what does that say about CFCF?

open on YouTube

Try it

Problem 33.6.19(additional)

AMC 10

Convex quadrilateral ABCDABCD has AB=9AB = 9 and CD=12CD = 12. Diagonals ACAC and BDBD intersect at EE, AC=14AC = 14, and △AED\triangle AED and △BEC\triangle BEC have equal areas. What is AEAE?

Contest cornerreal contest problems

Problem 33.6.10

AMC 12

Let ABCDABCD be a parallelogram with area 1515. Points PP and QQ are the projections of AA and CC, respectively, onto the line BDBD; and points RR and SS are the projections of BB and DD, respectively, onto the line ACAC. See the figure, which also shows the relative locations of these points.

Suppose PQ=6PQ = 6 and RS=8RS = 8, and let dd denote the length of BD‾\overline{BD}, the longer diagonal of ABCDABCD. Then d2d^2 can be written in the form m+npm + n\sqrt{p}, where mm, nn, and pp are positive integers and pp is not divisible by the square of any prime. What is m+n+pm + n + p?

Problem 33.6.25(additional)

AIME

In the diagram below, ABCDABCD is a rectangle with side lengths AB=3AB = 3 and BC=11BC = 11, and AECFAECF is a rectangle with side lengths AF=7AF = 7 and FC=9FC = 9, as shown. The area of the shaded region common to the interiors of both rectangles is mn\frac{m}{n}, where mm and nn are relatively prime positive integers. Find m+nm + n.

Checkpoint for section 33.4

Get 2 of 3 right to master this section. One try each, no hints.
1

A parallelogram has a side of length 99, and the distance between that side and the opposite side is 44. What is its area?

2

A parallelogram has diagonals 1010 and 66 that meet at a 30∘30^\circ angle. What is its area?

3

In parallelogram ABCDABCD, ∠A=70∘\angle A = 70^\circ. What is ∠B\angle B in degrees?

33.50%

Trapezoid

In this section you will be able to find a trapezoid's area, and use the triangles its diagonals make.

Average the two bases and multiply by the height. Why? Two copies of a trapezoid make a parallelogram.

A trapezoid with bases b1b_1, b2b_2 and height hh has area b1+b22⋅h\frac{b_1 + b_2}{2} \cdot h.

Look:

Draw both diagonals. The two triangles on the legs always have equal area, and the triangles on the bases are similar, with ratio b1:b2b_1 : b_2.

Exploreplay first, formulas later

Trapezoid: area 16, perimeter ≈16.25

5√173√17h = 4ABCD
Trapezoid

Two copies make a parallelogram: base b₁ + b₂ = 8, height 4, area 32. One trapezoid is half of it.

  • All 4 sides equal: no
  • 4 right angles: no
  • Both pairs of opposite sides parallel: no
  • At least one pair of opposite sides parallel: yes
  • Diagonals are equal: yes
  • Diagonals are perpendicular: yes
  • Diagonals cut each other in half: no
Trapezoid: area 16, perimeter ≈16.25

Trapezoid. Area 16, perimeter ≈16.25. At least one pair of opposite sides parallel; Diagonals are equal; Diagonals are perpendicular.

Name it

Theorem 33.5.1 · Area of a Trapezoid

A trapezoid with bases b1b_1 and b2b_2 and height hh has an area of

b1+b22⋅h.\frac{b_1 + b_2}{2} \cdot h.

Quadrilateral ABCD: 13.33 + 6.67 + 3.33 + 6.67 = 30

K13.336.673.336.67ABCD
13.33 + 6.67 + 3.33 + 6.67 = 30

ABCD cut into 4 pieces: 13.33 + 6.67 + 3.33 + 6.67 = 30.

Watch itpredict, then reveal

Example 33.3

AMC 12

Let ABCDABCD be an isosceles trapezoid with BC‾∥AD‾\overline{BC} \parallel \overline{AD} and AB=CDAB = CD. Points XX and YY lie on diagonal AC‾\overline{AC} with XX between AA and YY, as shown in the figure. Suppose ∠AXD=∠BYC=90∘\angle AXD = \angle BYC = 90^\circ, AX=3AX = 3, XY=1XY = 1, and YC=2YC = 2. What is the area of ABCDABCD?

Split into triangles (its total is revealed at the end of the example)

312ABCDXY
Quadrilateral ABCD

ABCD.

  1. 1

    How long is the diagonal ACAC?

    Predict first:
open on YouTube

Try it

Problem 33.6.24(additional)

AMC 10

Trapezoid ABCDABCD has bases AB‾\overline{AB} and CD‾\overline{CD} and diagonals intersecting at KK. Suppose that AB=9AB = 9, DC=12DC = 12, and the area of △AKD\triangle AKD is 2424. What is the area of trapezoid ABCDABCD?

Quadrilateral ABCD, cut into 4 pieces

K24912ABCD
4 pieces: △ABK, △BCK, △CDK, △DAK

ABCD cut into 4 pieces.

Problem 33.6.27(additional)

AMC 10

In trapezoid ABCDABCD we have AB‾\overline{AB} parallel to DC‾\overline{DC}, EE as the midpoint of BC‾\overline{BC}, and FF as the midpoint of DA‾\overline{DA}. The area of ABEFABEF is twice the area of FECDFECD. What is AB/DCAB/DC?

Problem 33.6.17(additional)

AMC 10

Consider the 12-sided polygon ABCDEFGHIJKLABCDEFGHIJKL, as shown. Each of its sides has length 44, and each two consecutive sides form a right angle. Suppose that AG‾\overline{AG} and CH‾\overline{CH} meet at MM. What is the area of quadrilateral ABCMABCM?

Contest cornerreal contest problems

Problem 33.6.8

AMC 12

What is the maximum area of an isosceles trapezoid that has legs of length 11 and one base twice as long as the other?

Problem 33.6.9

AMC 12

Let ABCDABCD be an isosceles trapezoid having parallel bases AB‾\overline{AB} and CD‾\overline{CD} with AB>CDAB > CD. Line segments from a point inside ABCDABCD to the vertices divide the trapezoid into four triangles whose areas are 2,3,4,2, 3, 4, and 55 starting with the triangle with base CD‾\overline{CD} and moving clockwise as shown in the diagram below. What is the ratio ABCD\frac{AB}{CD}?

Regions: PAB 4, PBC 3, PCD 2, PDA 5; whole figure 14

4325ABCDP
Whole = 14

Regions: PAB 4, PBC 3, PCD 2, PDA 5; whole figure 14

Problem 33.6.11

AMC 10/12

Isosceles trapezoid ABCDABCD has parallel sides AD‾\overline{AD} and BC‾\overline{BC}, with BC<ADBC < AD and AB=CDAB = CD. There is a point PP in the plane such that PA=1PA = 1, PB=2PB = 2, PC=3PC = 3, and PD=4PD = 4. What is BCAD\frac{BC}{AD}?

Click a choice or type its letter (A–E).

Problem 33.6.22(additional)

AMC 10

Trapezoid ABCDABCD has parallel sides AB‾\overline{AB} of length 3333 and CD‾\overline{CD} of length 2121. The other two sides are of lengths 1010 and 1414. The angles AA and BB are acute. What is the length of the shorter diagonal of ABCDABCD?

Problem 33.6.7

AMC 10/12

This problem also appears in the book as 32.2.3.

Trapezoid ABCDABCD has AB‾∥CD‾\overline{AB} \parallel \overline{CD}, BC=CD=43BC = CD = 43, and AD‾⊥BD‾\overline{AD} \perp \overline{BD}. Let OO be the intersection of the diagonals AC‾\overline{AC} and BD‾\overline{BD}, and let PP be the midpoint of BD‾\overline{BD}. Given that OP=11OP = 11, the length ADAD can be written in the form mnm\sqrt{n}, where mm and nn are positive integers and nn is not divisible by the square of any prime. What is m+nm + n?

Checkpoint for section 33.5

Get 2 of 3 right to master this section. One try each, no hints.
1

A trapezoid has bases 77 and 1313 and height 44. What is its area?

2

A trapezoid has area 6060, height 55 and one base 99. How long is the other base?

3

Consider the 12-sided polygon ABCDEFGHIJKLABCDEFGHIJKL, as shown. Each of its sides has length 44, and each two consecutive sides form a right angle. Suppose that AG‾\overline{AG} and CH‾\overline{CH} meet at MM. What is the area of quadrilateral ABCMABCM?

33.6

Practice Problems

In this section you will be able to mix every quadrilateral tool: split into triangles, fold, and set up coordinates.

No hint about which shape this time. Ask yourself: which triangle, which parallel lines, which fold?

Many of these are faster with coordinates. Put a right angle at the origin and let the algebra do the work.

Contest cornerreal contest problems

Problem 33.6.1

AMC 12

Convex quadrilateral ABCDABCD has AB=3AB = 3, BC=4BC = 4, CD=13CD = 13, AD=12AD = 12, and ∠ABC=90∘\angle ABC = 90^\circ, as shown. What is the area of the quadrilateral?

Problem 33.6.5

AMC 10

A square piece of paper has side length 11 and vertices A,B,C,A, B, C, and DD in that order. As shown in the figure the paper is folded so that vertex CC meets edge AD‾\overline{AD} at point C′C', and edge BC‾\overline{BC} intersects edge AB‾\overline{AB} at point EE. Suppose that C′D=13C'D = \frac{1}{3}. What is the perimeter of △AEC′\triangle AEC'?

Fold C onto C′: the crease GQ is the perpendicular bisector of CC′

GQEABCDB′C′
Crease GQ ⊥ CC′

Fold C onto C′: the crease GQ is the perpendicular bisector of CC′

Problem 33.6.15(additional)

AMC 10

This problem also appears in the book as 32.2.24.

Rectangle ABCDABCD has AB=3AB = 3 and BC=4BC = 4. Point EE is the foot of the perpendicular from BB to diagonal AC‾\overline{AC}. What is the area of △AED\triangle AED?

Problem 33.6.16(additional)

AMC 12

The internal angles of quadrilateral ABCDABCD form an arithmetic progression. Triangles ABDABD and DCBDCB are similar with ∠DBA=∠DCB\angle DBA = \angle DCB and ∠ADB=∠CBD\angle ADB = \angle CBD. Moreover, the angles in each of these two triangles also form an arithmetic progression. In degrees, what is the largest possible sum of the two largest angles of ABCDABCD?

Problem 33.6.18(additional)

AIME

This problem also appears in the book as 33.1.

Let ABCDABCD be a square, and let EE and FF be points on AB‾\overline{AB} and BC‾\overline{BC}, respectively. The line through EE parallel to BC‾\overline{BC} and the line through FF parallel to AB‾\overline{AB} divide ABCDABCD into two squares and two nonsquare rectangles. The sum of the areas of the two squares is 910\frac{9}{10} of the area of square ABCDABCD. Find AEEB+EBAE\frac{AE}{EB} + \frac{EB}{AE}.

Problem 33.6.28(additional)

AIME

ABCDABCD is a rectangular sheet of paper that has been folded so that corner BB is matched with point B′B' on edge ADAD. The crease is EFEF, where EE is on ABAB and FF is on CDCD. The dimensions AE=8AE = 8, BE=17BE = 17, and CF=3CF = 3 are given. The perimeter of rectangle ABCDABCD is m/nm/n, where mm and nn are relatively prime positive integers. Find m+nm + n.

Fold B onto B′: the crease EF is the perpendicular bisector of BB′

EFABCDC′B′
Crease EF ⊥ BB′

Fold B onto B′: the crease EF is the perpendicular bisector of BB′

Problem 33.6.29(additional)

AIME

In convex quadrilateral KLMNKLMN side MN‾\overline{MN} is perpendicular to diagonal KM‾\overline{KM}, side KL‾\overline{KL} is perpendicular to diagonal LN‾\overline{LN}, MN=65MN = 65, and KL=28KL = 28. The line through LL perpendicular to side KN‾\overline{KN} intersects diagonal KM‾\overline{KM} at OO with KO=8KO = 8. Find MOMO.