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Divisibility & Legendre's Formula: all problems

Focus mode: every practice problem from the chapter, one after another.

0 / 15 solved

Problem 22.1.1

AMC 10

A rectangular floor that is 1010 feet wide and 1717 feet long is tiled with 170170 one-foot square tiles. A bug walks from one corner to the opposite corner in a straight line. Including the first and the last tile, how many tiles does the bug visit?

Problem 22.1.2

AMC 12

This problem also appears in the book as 21.3.15.

How many odd positive 33-digit integers are divisible by 33 but do not contain the digit 33?

Problem 22.1.3

AMC 10

For all integers n≥9n \ge 9, the value of

(n+2)!−(n+1)!n!\frac{(n + 2)! - (n + 1)!}{n!}

is always which of the following?

Click a choice or type its letter (A–E).

Problem 22.1.4

IMO

Prove that the fraction 21n+414n+3\frac{21n + 4}{14n + 3} is irreducible for every natural number nn.

This one asks for a proof. Write yours on paper, use the hints if you need them, then compare it with the written proof.

Problem 22.1.5

AIME

What is the largest positive integer nn for which n3+100n^3 + 100 is divisible by n+10n + 10?

Problem 22.1.6

AMC 10

Call a positive integer an uphill integer if every digit is strictly greater than the previous digit. For example, 13571357, 8989, 55 are all uphill integers but 3232, 12401240, 466466 are not. How many uphill integers are divisible by 1515?

Problem 22.1.7(additional)

AMC 10

What is the largest integer that is a divisor of

(n+1)(n+3)(n+5)(n+7)(n+9)(n + 1)(n + 3)(n + 5)(n + 7)(n + 9)

for all positive even integers nn?

Problem 22.1.8(additional)

AMC 12

The number 21!=51,090,942,171,709,440,00021! = 51{,}090{,}942{,}171{,}709{,}440{,}000 has over 60,00060{,}000 positive integer divisors. One of them is chosen at random. What is the probability that it is odd?

Problem 22.1.9(additional)

AMC 10

This problem also appears in the book as 22.1.6.

Call a positive integer an uphill integer if every digit is strictly greater than the previous digit. For example, 13571357, 8989, and 55 are all uphill integers, but 3232, 12401240, and 466466 are not. How many uphill integers are divisible by 1515?

Problem 22.1.10(additional)

AMC 10

This problem also appears in the book as 21.3.20.

Let N=123456789101112…4344N = 123456789101112 \dots 4344 be the 7979-digit number that is formed by writing the integers from 11 to 4444 in order, one after the other. What is the remainder when NN is divided by 4545?

Problem 22.1.11(additional)

AMC 10

This problem also appears in the book as 22.1.

Let nn denote the smallest positive integer that is divisible by both 44 and 99, and whose base-10 representation consists of only 44's and 99's, with at least one of each. What are the last four digits of nn?

Problem 22.1.12(additional)

AMC 10

A finite sequence of three-digit integers has the property that the tens and units digits of each term are, respectively, the hundreds and tens digits of the next term, and the tens and units digits of the last term are, respectively, the hundreds and tens digits of the first term. For example, such a sequence might begin with the terms 247247, 475475, and 756756 and end with the term 824824. Let SS be the sum of all the terms in the sequence. What is the largest prime factor that always divides SS?

Problem 22.1.13(additional)

AMC 10

For how many positive integers n≤1000n \le 1000 is

⌊998n⌋+⌊999n⌋+⌊1000n⌋\left\lfloor \frac{998}{n} \right\rfloor + \left\lfloor \frac{999}{n} \right\rfloor + \left\lfloor \frac{1000}{n} \right\rfloor

not divisible by 33? (Recall that ⌊x⌋\lfloor x \rfloor is the greatest integer less than or equal to xx.)

Problem 22.1.14(additional)

AIME

Let a10=10a_{10} = 10, and for each positive integer n>10n > 10 let an=100an−1+na_n = 100a_{n-1} + n. Find the least positive n>10n > 10 such that ana_n is a multiple of 9999.

Problem 22.1.15(additional)

AIME

Define n!!n!! to be n(n−2)(n−4)⋯3⋅1n(n - 2)(n - 4) \cdots 3 \cdot 1 for nn odd and n(n−2)(n−4)⋯4⋅2n(n - 2)(n - 4) \cdots 4 \cdot 2 for nn even. When

∑i=12009(2i−1)!!(2i)!!\sum_{i=1}^{2009} \frac{(2i - 1)!!}{(2i)!!}

is expressed as a fraction in lowest terms, its denominator is 2ab2^a b with bb odd. Find ab10\dfrac{ab}{10}.