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Handbook · Chapter 5

Trigonometry

Trig identities and special values, the unit circle, the laws of sines and cosines, double, half and sum angle formulas, and the graphs of the trig functions.

Book pages 113–123 · 18 entries

5.1 Trigonometric Identities

Theorem 5.1.1 · Trigonometric Identities

In a right triangle with an acute angle aa:

Sine: sin⁡(a)=OppositeHypotenuse\text{Sine: } \sin(a) = \frac{\text{Opposite}}{\text{Hypotenuse}}
Cosine: cos⁡(a)=AdjacentHypotenuse\text{Cosine: } \cos(a) = \frac{\text{Adjacent}}{\text{Hypotenuse}}
Tangent: tan⁡(a)=OppositeAdjacent=sin⁡(a)cos⁡(a)\text{Tangent: } \tan(a) = \frac{\text{Opposite}}{\text{Adjacent}} = \frac{\sin(a)}{\cos(a)}

Learn it:Theorem 42.1.1 · Trigonometric Identities

Book p. 113Checked numerically

Remark 5.1.2

To remember the relationships, just use the mnemonic SOH, CAH, TOA:

  • SOH = Sin is Opposite over Hypotenuse
  • CAH = Cos is Adjacent over Hypotenuse
  • TOA = Tan is Opposite over Adjacent

Learn it:Remark 42.1.2

Book p. 114

5.2 More Trigonometric Identities

Theorem 5.2.1 · More Trigonometric Identities

Cosecant: csc⁡(a)=HypotenuseOpposite=1sin⁡(a)\text{Cosecant: } \csc(a) = \frac{\text{Hypotenuse}}{\text{Opposite}} = \frac{1}{\sin(a)}
Secant: sec⁡(a)=HypotenuseAdjacent=1cos⁡(a)\text{Secant: } \sec(a) = \frac{\text{Hypotenuse}}{\text{Adjacent}} = \frac{1}{\cos(a)}
Cotangent: cot⁡(a)=AdjacentOpposite=1tan⁡(a)=cos⁡(a)sin⁡(a)\text{Cotangent: } \cot(a) = \frac{\text{Adjacent}}{\text{Opposite}} = \frac{1}{\tan(a)} = \frac{\cos(a)}{\sin(a)}

Learn it:Theorem 42.2.1 · More Trigonometric Identities

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5.3 Important Trigonometric Values

The book's table of values (unnumbered). The values from 90∘90^\circ to 180∘180^\circ follow from those below 90∘90^\circ by sin⁡(180∘−a)=sin⁡a\sin(180^\circ - a) = \sin a and cos⁡(180∘−a)=−cos⁡a\cos(180^\circ - a) = -\cos a.

aa cos⁡a\cos a sin⁡a\sin a
0∘0^\circ 11 00
15∘15^\circ 3+122\frac{\sqrt3+1}{2\sqrt2} 3−122\frac{\sqrt3-1}{2\sqrt2}
30∘30^\circ 32\frac{\sqrt3}{2} 12\frac12
45∘45^\circ 22\frac{\sqrt2}{2} 22\frac{\sqrt2}{2}
60∘60^\circ 12\frac12 32\frac{\sqrt3}{2}
75∘75^\circ 3−122\frac{\sqrt3-1}{2\sqrt2} 3+122\frac{\sqrt3+1}{2\sqrt2}
90∘90^\circ 00 11
120∘120^\circ −12-\frac12 32\frac{\sqrt3}{2}
135∘135^\circ −22-\frac{\sqrt2}{2} 22\frac{\sqrt2}{2}
150∘150^\circ −32-\frac{\sqrt3}{2} 12\frac12
180∘180^\circ −1-1 00

Correction. The book prints cos⁡180∘=1\cos 180^\circ = 1; it is −1-1 (the point (−1,0)(-1, 0) of the unit circle). It also prints the row cos⁡0∘=1\cos 0^\circ = 1, sin⁡0∘=0\sin 0^\circ = 0 twice and labels the last sine sin⁡0∘\sin 0^\circ instead of sin⁡180∘\sin 180^\circ; this table shows each angle once.

5.4 Unit Circle Identities

Theorem 5.4.1 · Unit Circle Identities

sin⁡(−a)=−sin⁡(a)\sin(-a) = -\sin(a)
sin⁡(a)=sin⁡(180∘−a)\sin(a) = \sin(180^\circ - a)
cos⁡(a)=cos⁡(−a)\cos(a) = \cos(-a)
cos⁡(a)=−cos⁡(180∘−a)\cos(a) = -\cos(180^\circ - a)
tan⁡(a)=−tan⁡(180∘−a)\tan(a) = -\tan(180^\circ - a)
tan⁡(−a)=−tan⁡(a)\tan(-a) = -\tan(a)

Learn it:Theorem 42.4.1 · Unit Circle IdentitiesSection 42.3 Special Angles and the Unit Circle

Book p. 116Checked numerically

5.5 Area of a Triangle using trigonometry

Theorem 5.5.1 · Area of a Triangle using trigonometry

In a triangle with side lengths aa, bb, cc, where the angle between sides aa and bb is denoted by CC,

Area of the triangle=12⋅ab⋅sin⁡(C)\text{Area of the triangle} = \frac{1}{2} \cdot ab \cdot \sin(C)

Learn it:Theorem 43.1.1 · Area of a Triangle Using Trigonometry

Book p. 117Checked numerically

5.6 Law of Sines

Theorem 5.6.1 · Law of Sines

In a triangle with sides aa, bb, cc and angles AA, BB, CC, where side aa is opposite angle AA, side bb is opposite angle BB, and side cc is opposite angle CC,

asin⁡A=bsin⁡B=csin⁡C=2R\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} = 2R

where RR is the circumradius of the triangle.

Learn it:Theorem 43.2.1 · Law of Sines

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5.7 Law of Cosines

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Theorem 5.7.1 · Law of Cosines

In a triangle with side lengths aa, bb, cc, where the angle between sides aa and bb is denoted by CC,

c2=a2+b2−2ab⋅cos⁡Cc^2 = a^2 + b^2 - 2ab \cdot \cos C

Learn it:Theorem 43.3.1 · Law of Cosines

Book p. 118Checked numerically

5.8 Pythagorean Identities

Theorem 5.8.1 · Pythagorean Identities

sin⁡2(a)+cos⁡2(a)=1\sin^2(a) + \cos^2(a) = 1
tan⁡2(a)+1=sec⁡2(a)\tan^2(a) + 1 = \sec^2(a)
cot⁡2(a)+1=csc⁡2(a)\cot^2(a) + 1 = \csc^2(a)

a = 40°: P = (cos a, sin a) = (0.766, 0.6428); tan a = 0.8391. Tangent segment 0.8391, secant segment 1.3054.

Angle a40°
a=40∘a = 40^\circ
P=(cos⁡a, sin⁡a)P=(\cos a,\ \sin a)
ff(40°)
cos a0.7660.766
sin a0.64280.6428
tan a0.83910.8391

a = 40°: P = (cos a, sin a) = (0.766, 0.6428); tan a = 0.8391. Tangent segment 0.8391, secant segment 1.3054.

Learn it:Theorem 42.5.1 · Pythagorean Identities

Book p. 119Checked numerically

5.9 Double Angle Identities

Theorem 5.9.1 · Double Angle Identities

sin⁡(2a)=2sin⁡(a)cos⁡(a)\sin(2a) = 2\sin(a)\cos(a)
cos⁡(2a)=cos⁡2(a)−sin⁡2(a)=2cos⁡2(a)−1=1−2sin⁡2(a)\cos(2a) = \cos^2(a) - \sin^2(a) = 2\cos^2(a) - 1 = 1 - 2\sin^2(a)
tan⁡(2a)=2tan⁡(a)1−tan⁡2(a)\tan(2a) = \frac{2\tan(a)}{1 - \tan^2(a)}

Learn it:Theorem 42.6.1 · Double Angle Identities

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5.10 Addition and Subtraction Identities

Theorem 5.10.1 · Addition and Subtraction Identities

sin⁡(a+b)=sin⁡(a)cos⁡(b)+sin⁡(b)cos⁡(a)\sin(a + b) = \sin(a)\cos(b) + \sin(b)\cos(a)
sin⁡(a−b)=sin⁡(a)cos⁡(b)−sin⁡(b)cos⁡(a)\sin(a - b) = \sin(a)\cos(b) - \sin(b)\cos(a)
cos⁡(a+b)=cos⁡(a)cos⁡(b)−sin⁡(a)sin⁡(b)\cos(a + b) = \cos(a)\cos(b) - \sin(a)\sin(b)
cos⁡(a−b)=cos⁡(a)cos⁡(b)+sin⁡(a)sin⁡(b)\cos(a - b) = \cos(a)\cos(b) + \sin(a)\sin(b)
tan⁡(a+b)=tan⁡(a)+tan⁡(b)1−tan⁡(a)tan⁡(b)\tan(a + b) = \frac{\tan(a) + \tan(b)}{1 - \tan(a)\tan(b)}
tan⁡(a−b)=tan⁡(a)−tan⁡(b)1+tan⁡(a)tan⁡(b)\tan(a - b) = \frac{\tan(a) - \tan(b)}{1 + \tan(a)\tan(b)}

Learn it:Theorem 42.7.1 · Addition and Subtraction Identities

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5.11 Half Angle Identities

Theorem 5.11.1 · Half Angle Identities

sin⁡(a2)=±1−cos⁡(a)2\sin\left(\frac a2\right) = \pm\sqrt{\frac{1 - \cos(a)}{2}}
cos⁡(a2)=±1+cos⁡(a)2\cos\left(\frac a2\right) = \pm\sqrt{\frac{1 + \cos(a)}{2}}

The sign is the sign of sin⁡a2\sin\frac a2 (or cos⁡a2\cos\frac a2): look at the quadrant of a2\frac a2.

Learn it:Theorem 42.8.1 · Half Angle Identities

Book p. 121Checked numerically

5.12 Sum to Product Identities

Theorem 5.12.1 · Sum to Product Identities

sin⁡(a)+sin⁡(b)=2sin⁡(a+b2)cos⁡(a−b2)\sin(a) + \sin(b) = 2\sin\left(\frac{a+b}{2}\right)\cos\left(\frac{a-b}{2}\right)
sin⁡(a)−sin⁡(b)=2sin⁡(a−b2)cos⁡(a+b2)\sin(a) - \sin(b) = 2\sin\left(\frac{a-b}{2}\right)\cos\left(\frac{a+b}{2}\right)
cos⁡(a)+cos⁡(b)=2cos⁡(a−b2)cos⁡(a+b2)\cos(a) + \cos(b) = 2\cos\left(\frac{a-b}{2}\right)\cos\left(\frac{a+b}{2}\right)
cos⁡(a)−cos⁡(b)=−2sin⁡(a−b2)sin⁡(a+b2)\cos(a) - \cos(b) = -2\sin\left(\frac{a-b}{2}\right)\sin\left(\frac{a+b}{2}\right)

Learn it:Theorem 42.9.1 · Sum to Product Identities

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5.13 Product to Sum Identities

Theorem 5.13.1 · Product to Sum Identities

sin⁡(a)sin⁡(b)=12(cos⁡(a−b)−cos⁡(a+b))\sin(a)\sin(b) = \frac12\left(\cos(a - b) - \cos(a + b)\right)
cos⁡(a)cos⁡(b)=12(cos⁡(a−b)+cos⁡(a+b))\cos(a)\cos(b) = \frac12\left(\cos(a - b) + \cos(a + b)\right)
sin⁡(a)cos⁡(b)=12(sin⁡(a+b)+sin⁡(a−b))\sin(a)\cos(b) = \frac12\left(\sin(a + b) + \sin(a - b)\right)

Learn it:Theorem 42.10.1 · Product to Sum Identities

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Definition 5.13.2

A periodic function is a function that repeats a pattern of yy-values at regular intervals. One complete repetition of the pattern is called a cycle. The period of a function is the horizontal length of one complete cycle.

The period of sin⁡\sin and cos⁡\cos is 2π2\pi; the period of tan⁡\tan is π\pi.

Correction

The book says the period of sin⁡\sin, cos⁡\cos and tan⁡\tan is 2π2\pi. Tangent repeats after only π\pi: tan⁡(x+π)=−sin⁡x−cos⁡x=tan⁡x\tan(x + \pi) = \frac{-\sin x}{-\cos x} = \tan x. (The book also calls every periodic function "trigonometric"; periodic is the general word.)

Learn it:Definition 42.11.1 · Periodic function

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5.14 Periods and Graphs of Trigonometric Functions

Concept 5.14.1 · Sine Graph

The graph of y=sin⁡xy = \sin x is a wave between −1-1 and 11. It starts at (0,0)(0, 0), peaks at x=π2x = \frac\pi2, crosses zero at every multiple of π\pi, and repeats every 2π2\pi.

sin x = 0 on [−2π, 2π]: 5 solutions (3 crossings, 0 tangencies, 2 at a closed end).

— f(x) = sin x
[−2π, 2π]: 5 solutions

3 crossings, 0 tangencies, 2 at a closed end

sin x = 0 on [−2π, 2π]: 5 solutions (3 crossings, 0 tangencies, 2 at a closed end).

Learn it:Concept 42.12.1 · Sine Graph

Book p. 122

Concept 5.14.2 · Cosine Graph

The graph of y=cos⁡xy = \cos x is the sine wave shifted left by π2\frac\pi2: cos⁡x=sin⁡(x+π2)\cos x = \sin\left(x + \frac\pi2\right). It starts at its peak (0,1)(0, 1), crosses zero at odd multiples of π2\frac\pi2, and repeats every 2π2\pi.

cos x = 0 on [−2π, 2π]: 4 solutions (4 crossings, 0 tangencies, 0 at a closed end).

— f(x) = cos x
[−2π, 2π]: 4 solutions

4 crossings, 0 tangencies, 0 at a closed end

cos x = 0 on [−2π, 2π]: 4 solutions (4 crossings, 0 tangencies, 0 at a closed end).

Learn it:Concept 42.12.2 · Cosine Graph

Book p. 122

Concept 5.14.3 · Tan Graph

The graph of y=tan⁡xy = \tan x crosses zero at every multiple of π\pi and shoots off to ±∞\pm\infty at the vertical asymptotes x=π2+kπx = \frac\pi2 + k\pi, where cos⁡x=0\cos x = 0. It repeats every π\pi.

tan x = 0 on [−2π, 2π]: 5 solutions (3 crossings, 0 tangencies, 2 at a closed end).

— f(x) = tan x
[−2π, 2π]: 5 solutions

3 crossings, 0 tangencies, 2 at a closed end

tan x = 0 on [−2π, 2π]: 5 solutions (3 crossings, 0 tangencies, 2 at a closed end).

Learn it:Concept 42.12.3 · Tan Graph

Book p. 122